tag:blogger.com,1999:blog-7115633791110477890.post6323472397092335580..comments2024-02-07T00:26:17.605-08:00Comments on Cuebidding At Bridge: Deep ThoughtsKenneth Rexford, Esq.http://www.blogger.com/profile/03546227934953411090noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-7115633791110477890.post-78781315490990407992010-08-19T19:59:30.297-07:002010-08-19T19:59:30.297-07:00That is, 6S in (4).That is, 6S in (4).Kenneth Rexford, Esq.https://www.blogger.com/profile/03546227934953411090noreply@blogger.comtag:blogger.com,1999:blog-7115633791110477890.post-87024341560205938572010-08-19T19:58:47.028-07:002010-08-19T19:58:47.028-07:006KCB doesn't seem to solve the problem in all ...6KCB doesn't seem to solve the problem in all situations, because the question is not how many internal Queens, but WHICH internal Queen. This is even worse when it the scenario could be that we could have:<br /><br />1. King of spades, Queen of clubs<br />2. King of clubs, Queen of spades<br />3. King and Queen of clubs<br />4. King and Queen of spades<br /><br />It could easily be the case that in (3), we want to play 6C, in (4) we want to play in 6C, but in (1) or (2) we want to sign off at 5S. 6KCB doesn't seem to answer which King or which Queen.Kenneth Rexford, Esq.https://www.blogger.com/profile/03546227934953411090noreply@blogger.comtag:blogger.com,1999:blog-7115633791110477890.post-12549156644912736862010-08-19T15:56:34.924-07:002010-08-19T15:56:34.924-07:00On this auction (1S 2C; 3C 3S), would you use 6-ca...On this auction (1S 2C; 3C 3S), would you use 6-card RKC? If so, how would that work into this?Memphis MOJOhttps://www.blogger.com/profile/12653631347560307425noreply@blogger.com